Java examples for java.lang:String End
returns the FIRST string in str that is bounded on the left by leftBound, and bounded on the right by rightBound.
//package com.java2s; public class Main { public static void main(String[] argv) { String str = "java2s.com"; String leftBound = "b"; String rightBound = "com"; System.out.println(getBoundedString(str, leftBound, rightBound)); }/*from ww w . j ava2s. co m*/ /** * This returns the FIRST string in str that is bounded on the left by * leftBound, and bounded on the right by rightBound. This will return null * if the leftBound is not found within str. * * <P> * If leftBound can't be found this returns null. * </P> * <P> * This rightBound can't be found then this throws a * StringIndexOutOfBoundsException. * </P> * * @param str * the base string that we will search for the bounded string. * @param leftBound * the left bound of the string. * @param rightBound * the right bound of the string. */ public static String getBoundedString(String str, String leftBound, String rightBound) throws RuntimeException { if (str == null) { throw new RuntimeException("string to parse is null?"); } int startPos = str.indexOf(leftBound); if (startPos > -1) { startPos = startPos + leftBound.length(); int endPos = str.indexOf(rightBound, startPos); // dp(str+" start:"+startPos+" end:"+endPos); if (endPos == -1) { throw new RuntimeException("Can't find rightBound: " + rightBound); } return str.substring(startPos, endPos); } else { // if no leftBound can be found.. return null... could be in a // search n parse type loop? // this keeps "no tag"==null different from "tag not formed // properly"==StringParsingException return null; } } }