Java examples for java.lang:Math Number
Generates all permutations of a sequence containing the numbers from 1 to n.
/* Copyright 2012-2015 SAP SE * * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License./*from ww w.j av a2 s. co m*/ */ //package com.java2s; import java.util.ArrayList; import java.util.List; public class Main { private static int permLevel = -1; /** * Generates all permutations of a sequence containing the numbers from 1 to * n. * * @param n * The upper bound of the permutations. * @return A List with all permutations of the sequence. */ public static List<int[]> generateLocationPermutations(int n) { List<int[]> res = new ArrayList<int[]>(); permLevel = -1; int[] value = new int[n]; for (int i = 0; i < value.length; i++) { value[i] = 0; } permVisit(value, n, 0, res); return res; } /** * Helper method for generating the integer sequence permutations. Should * not be used on its own! * */ private static void permVisit(int[] value, int n, int k, List<int[]> res) { permLevel = permLevel + 1; value[k] = permLevel; if (permLevel == n) { res.add(copySubarray(value, 0, value.length)); } else { for (int i = 0; i < n; i++) { if (value[i] == 0) permVisit(value, n, i, res); } } permLevel = permLevel - 1; value[k] = 0; } /** * Copies a subarray of a given array and returns it. * * @param src * The source array that should be used. * @param start * The start index. * @param end * The end index. * @return A subarray of the source array, including the value at the start * index and excluding the value at the end index. */ private static int[] copySubarray(int[] src, int start, int end) { int[] res = new int[end - start]; int resPos = 0; for (int i = start; i < end; i++) { res[resPos] = src[i]; resPos++; } return res; } }