Find the point on the line p0,p1 [x,y,z] a given fraction from p0. - Java java.lang

Java examples for java.lang:Math Geometry Line

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Description

Find the point on the line p0,p1 [x,y,z] a given fraction from p0.

Demo Code



public class Main{
    /**/*from   w w w  .j  a  v  a2s  .c o  m*/
     * Find the point on the line p0,p1 [x,y,z] a given fraction from p0.
     * Fraction of 0.0 whould give back p0, 1.0 give back p1, 0.5 returns
     * midpoint of line p0,p1 and so on. F raction can be >1 and it can be
     * negative to return any point on the line specified by p0,p1.
     *
     * @param p0 First coordinale of line [x,y,z].
     * @param p0 Second coordinale of line [x,y,z].
     * @param fractionFromP0 Point we are looking for coordinates of
     * @param p Coordinate of point we are looking for
     */
    public static double[] computePointOnLine(double[] p0, double[] p1,
            double fractionFromP0) {
        double[] p = new double[3];

        p[0] = p0[0] + fractionFromP0 * (p1[0] - p0[0]);
        p[1] = p0[1] + fractionFromP0 * (p1[1] - p0[1]);
        p[2] = p0[2] + fractionFromP0 * (p1[2] - p0[2]);

        return p;
    }
    /**
     * Find the point on the line defined by x0,y0,x1,y1 a given fraction from
     * x0,y0. 2D version of method above..
     *
     * @param x0, y0 First point defining the line
     * @param x1, y1 Second point defining the line
     * @param fractionFrom0 Distance from (x0,y0)
     * @return x, y Coordinate of point we are looking for
     */
    public static double[] computePointOnLine(double x0, double y0,
            double x1, double y1, double fractionFrom0) {
        double[] p0 = { x0, y0, 0.0 };
        double[] p1 = { x1, y1, 0.0 };

        double[] p = GeometryUtils
                .computePointOnLine(p0, p1, fractionFrom0);

        double[] r = { p[0], p[1] };
        return r;
    }
}

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