Java examples for Internationalization:Charset
Returns true if the specified character is a whitespace character (CR, LF, SP or HT).
/**************************************************************** * Licensed to the Apache Software Foundation (ASF) under one * * or more contributor license agreements. See the NOTICE file * * distributed with this work for additional information * * regarding copyright ownership. The ASF licenses this file * * to you under the Apache License, Version 2.0 (the * * "License"); you may not use this file except in compliance * * with the License. You may obtain a copy of the License at * * * * http://www.apache.org/licenses/LICENSE-2.0 * * * * Unless required by applicable law or agreed to in writing, * * software distributed under the License is distributed on an * * "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY * * KIND, either express or implied. See the License for the * * specific language governing permissions and limitations * * under the License. * ****************************************************************/ //package com.java2s; public class Main { public static void main(String[] argv) throws Exception { char ch = 'a'; System.out.println(isWhitespace(ch)); }//from w w w. j av a 2s.com /** US-ASCII CR, carriage return (13) */ public static final int CR = '\r'; /** US-ASCII LF, line feed (10) */ public static final int LF = '\n'; /** US-ASCII SP, space (32) */ public static final int SP = ' '; /** US-ASCII HT, horizontal-tab (9) */ public static final int HT = '\t'; /** * Returns <code>true</code> if the specified character is a whitespace * character (CR, LF, SP or HT). * * @param ch * character to test. * @return <code>true</code> if the specified character is a whitespace * character, <code>false</code> otherwise. */ public static boolean isWhitespace(char ch) { return ch == SP || ch == HT || ch == CR || ch == LF; } /** * Returns <code>true</code> if the specified string consists entirely of * whitespace characters. * * @param s * string to test. * @return <code>true</code> if the specified string consists entirely of * whitespace characters, <code>false</code> otherwise. */ public static boolean isWhitespace(final String s) { if (s == null) { throw new IllegalArgumentException("String may not be null"); } final int len = s.length(); for (int i = 0; i < len; i++) { if (!isWhitespace(s.charAt(i))) { return false; } } return true; } }