Convert the given number of bytes to human-readable String format. - Java File Path IO

Java examples for File Path IO:Byte Array

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Description

Convert the given number of bytes to human-readable String format.

Demo Code

/**/*from   w w w.  j  a va 2s  . com*/
 *
 * jerry - Common Java Functionality
 * Copyright (c) 2012-2015, Sandeep Gupta
 * 
 * http://sangupta.com/projects/jerry
 * 
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 * 
 *       http://www.apache.org/licenses/LICENSE-2.0
 * 
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 * 
 */
import java.util.Arrays;

public class Main{
    public static void main(String[] argv) throws Exception{
        long bytes = 2;
        System.out.println(getReadableByteCount(bytes));
    }
    /**
     * Convert the given number of bytes to human-readable {@link String} format.
     * 
     * @param bytes
     * @return
     */
    public static String getReadableByteCount(long bytes) {
        if (bytes < FileUtils.ONE_KB) {
            return bytes + " B";
        }

        int exp = (int) (Math.log(bytes) / Math.log(FileUtils.ONE_KB));
        String pre = "" + "KMGTPE".charAt(exp - 1);
        double value = bytes / Math.pow(FileUtils.ONE_KB, exp);
        if (((value * 10) % 10) == 0) {
            return String.format("%.0f %sB", value, pre);
        }

        return String.format("%.1f %sB", value, pre);
    }
}

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