Java XPath Get get(String path, Node e)

Here you can find the source of get(String path, Node e)

Description

get

License

Apache License

Declaration

public static String get(String path, Node e) 

Method Source Code


//package com.java2s;
/*//from   www.ja  v a 2  s. c o m
 * Copyright 2012 LIG SIGMA
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *     http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

import org.w3c.dom.Node;

import javax.xml.namespace.QName;

import javax.xml.xpath.*;

import java.util.HashMap;
import java.util.Map;

public class Main {
    private static XPath xpath;
    private static Map<String, XPathExpression> compiledString = new HashMap<String, XPathExpression>();

    public static String get(String path, Node e) {
        return (String) evaluateXPath(path, e, XPathConstants.STRING);
    }

    private static Object evaluateXPath(String path, Node e, QName type) {
        try {
            XPathExpression expr = compiledString.get(path);
            if (expr == null) {
                expr = xpath.compile(path);
                compiledString.put(path, expr);
            }
            return expr.evaluate(e, type);
        } catch (XPathExpressionException e1) {
            throw new IllegalStateException("Wrong XPATH expression: " + path, e1);
            //SHOULD NEVER HAPPEN IF THE EXPRESSIONS ARE WELL MADE INSIDE THE CODE
        }
    }
}

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