Java XML Node Text Value getTextContent(Node node)

Description

get Text Content

License

Open Source License

Declaration

public static String getTextContent(Node node) 

Method Source Code

//package com.java2s;
//License from project: Open Source License 

import java.util.stream.IntStream;
import java.util.stream.Stream;

import org.w3c.dom.Node;
import org.w3c.dom.NodeList;

public class Main {
    /**/*w  w w  .  j  a  v  a 2 s.c om*/
     * Get text content of the first child node matching the given node name. Use this method instead of {@link #selectString(String, Object)} whenever xpath support is not required, because it is much faster, especially for large documents.
     *
     * @param childName
     *            search for nodes with this name
     * @param parentNode
     *            search in the child nodes of this nodes
     * @return text content of the child node or null if no child with the given name was found
     */
    public static String getTextContent(String childName, Node parentNode) {
        Node child = getChild(childName, parentNode);

        if (child == null) {
            return null;
        }

        return getTextContent(child);
    }

    public static String getTextContent(Node node) {
        StringBuilder sb = new StringBuilder();

        for (Node textNode : getChildren("#text", node)) {
            sb.append(textNode.getNodeValue());
        }

        return sb.toString().trim();
    }

    /**
     * @param nodeName
     *            search for nodes with this name
     * @param parentNode
     *            search in the child nodes of this nodes
     * @return text content of the child node or null if no child with the given name was found
     */
    public static Node getChild(String nodeName, Node parentNode) {
        if (parentNode == null) {
            return null;
        } else {
            return stream(parentNode.getChildNodes()).filter(n -> nodeName.equals(n.getNodeName())).findFirst()
                    .orElse(null);
        }
    }

    public static Node[] getChildren(String nodeName, Node parentNode) {
        if (parentNode == null) {
            return new Node[0];
        } else {
            return stream(parentNode.getChildNodes()).filter(n -> nodeName.equals(n.getNodeName()))
                    .toArray(Node[]::new);
        }
    }

    public static Stream<Node> stream(NodeList nodes) {
        return IntStream.range(0, nodes.getLength()).mapToObj(nodes::item);
    }
}

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