Java XML Node Get by Name getElementsByTagName(Node node, String tagName)

Description

get Elements By Tag Name

License

Apache License

Declaration

public static ArrayList<Element> getElementsByTagName(Node node, String tagName) 

Method Source Code

//package com.java2s;
//License from project: Apache License 

import java.util.ArrayList;

import org.w3c.dom.Element;
import org.w3c.dom.Node;

public class Main {
    public static ArrayList<Element> getElementsByTagName(Node node, String tagName) {
        ArrayList<Element> elements = new ArrayList<Element>();
        for (int i = 0; i < node.getChildNodes().getLength(); i++) {
            Node n = node.getChildNodes().item(i);
            if (n.getNodeType() == Node.ELEMENT_NODE && n.getNodeName().equals(tagName)) {
                elements.add((Element) n);
            }/*from  w  ww  .  ja  v  a2 s .  com*/
        }
        return elements;
    }
}

Related

1. getElementsByTagName(Node node, String tagname)
2. getElementsByTagName(Node node, String tagName)
3. getElementsByTagName(Node root, String tagName)
4. getElementsByTagNameNS(Node element, String namespace, String name)
5. getElementsByTagNames(Node node, String... tagName)