Java XML Node Find findAllDescendantElements(Node e, String qname, Collection vector)

Description

find All Descendant Elements

License

Open Source License

Declaration

static public int findAllDescendantElements(Node e, String qname, Collection vector) 

Method Source Code

//package com.java2s;
/*//  w  w  w.j a va2  s.c  o m
Copyright (c) 2005 Pierre Lindenbaum PhD
    
Permission is hereby granted, free of charge, to any person obtaining
a copy of this software and associated documentation files (the
``Software''), to deal in the Software without restriction, including
without limitation the rights to use, copy, modify, merge, publish,
distribute, sublicense, and/or sell copies of the Software, and to
permit persons to whom the Software is furnished to do so, subject to
the following conditions:
    
The above copyright notice and this permission notice shall be included
in all copies or substantial portions of the Software.
    
The name of the authors when specified in the source files shall be 
kept unmodified.
    
THE SOFTWARE IS PROVIDED ``AS IS'', WITHOUT WARRANTY OF ANY KIND, EXPRESS
OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF
MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT.
IN NO EVENT SHALL 4XT.ORG BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE,
ARISING FROM, OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE
USE OR OTHER DEALINGS IN THE SOFTWARE.
    
    
$Id: $
$Author: $
$Revision: $
$Date: $
$Locker: $
$RCSfile: $
$Source: $
$State: $
$Name: $
$Log: $
    
    
*************************************************************************/

import java.util.Collection;
import java.util.Vector;

import org.w3c.dom.*;

public class Main {
    static public Element[] findAllDescendantElements(Node e, String qname) {
        Vector v = new Vector();
        findAllDescendantElements(e, qname, v);
        Element array[] = new Element[v.size()];
        for (int i = 0; i < array.length; ++i) {
            array[i] = (Element) v.elementAt(i);
        }
        return array;
    }

    static public int findAllDescendantElements(Node e, String qname, Collection vector) {
        int n = 0;
        if (e == null || qname == null)
            return 0;
        for (Node c = e.getFirstChild(); c != null; c = c.getNextSibling()) {
            if (c.getNodeType() == Node.ELEMENT_NODE && c.getNodeName().equals(qname)) {
                ++n;
                vector.add((Element) c);
            }
            n += findAllDescendantElements(c, qname, vector);
        }
        return n;
    }
}

Related

1. findAllNodes(Node node, String[] nodeNames, ArrayList results)
2. findAllNodesRecursive(Node n, String name)
3. findAllProcessingIstructions(Node node, String name, List result)
4. findAllUrisRecursive(Node node, List nodes)