Java XML Has Child hasChildElementNodes(@Nonnull final Node aStartNode)

Here you can find the source of hasChildElementNodes(@Nonnull final Node aStartNode)

Description

Check if the passed node has at least one direct child element or not.

License

Apache License

Parameter

Parameter Description
aStartNode The parent element to be searched. May not be <code>null</code>.

Return

true if the passed node has at least one child element, false otherwise.

Declaration

public static boolean hasChildElementNodes(@Nonnull final Node aStartNode) 

Method Source Code

//package com.java2s;
/**//from  w ww .j av a 2  s.  c  o  m
 * Copyright (C) 2014-2015 Philip Helger (www.helger.com)
 * philip[at]helger[dot]com
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *         http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

import javax.annotation.Nonnegative;
import javax.annotation.Nonnull;
import javax.annotation.Nullable;

import org.w3c.dom.Element;

import org.w3c.dom.Node;
import org.w3c.dom.NodeList;

public class Main {
    /**
     * Check if the passed node has at least one direct child element or not.
     *
     * @param aStartNode
     *        The parent element to be searched. May not be <code>null</code>.
     * @return <code>true</code> if the passed node has at least one child
     *         element, <code>false</code> otherwise.
     */
    public static boolean hasChildElementNodes(@Nonnull final Node aStartNode) {
        return getFirstChildElement(aStartNode) != null;
    }

    /**
     * Get the first direct child element of the passed element.
     *
     * @param aStartNode
     *        The element to start searching.
     * @return <code>null</code> if the passed element does not have any direct
     *         child element.
     */
    @Nullable
    public static Element getFirstChildElement(@Nonnull final Node aStartNode) {
        final NodeList aNodeList = aStartNode.getChildNodes();
        final int nLen = aNodeList.getLength();
        for (int i = 0; i < nLen; ++i) {
            final Node aNode = aNodeList.item(i);
            if (aNode.getNodeType() == Node.ELEMENT_NODE)
                return (Element) aNode;
        }
        return null;
    }

    @Nonnegative
    public static int getLength(@Nullable final NodeList aNL) {
        return aNL == null ? 0 : aNL.getLength();
    }
}

Related

  1. hasChild(Node n)
  2. hasChildElement(Element elem, String namespace, String localName)
  3. hasChildElement(Element element, String name)
  4. hasChildElement(NodeList list)
  5. hasChildElement(TreeWalker walker)
  6. hasChildElements(Element element)
  7. hasChildElements(Element element)
  8. hasChildElements(Element element)
  9. hasChildElements(Node node)