Java XML First Child Element getFirstChildElement(Element elem)

Description

Return the first child element of the given element.

License

Apache License

Parameter

Parameter	Description
elem	Element whose child is to be returned

Return

the first child element.

Declaration

public static Element getFirstChildElement(Element elem) 

Method Source Code

//package com.java2s;
/*/*from  ww w . jav  a 2  s .  c  o  m*/
 * Licensed to the Apache Software Foundation (ASF) under one
 * or more contributor license agreements.  See the NOTICE file
 * distributed with this work for additional information
 * regarding copyright ownership.  The ASF licenses this file
 * to you under the Apache License, Version 2.0 (the
 * "License"); you may not use this file except in compliance
 * with the License.  You may obtain a copy of the License at
 *
 *    http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing,
 * software distributed under the License is distributed on an
 * "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY
 * KIND, either express or implied.  See the License for the
 * specific language governing permissions and limitations
 * under the License.
 */

import org.w3c.dom.Element;

import org.w3c.dom.Node;
import org.w3c.dom.NodeList;

public class Main {
    public static Element getFirstChildElement(Node node) {
        NodeList l = node.getChildNodes();
        for (int i = 0; i < l.getLength(); i++) {
            if (l.item(i) instanceof Element)
                return (Element) l.item(i);
        }
        return null;
    }

    /**
     * Return the first child element of the given element. Null if no children
     * are found.
     *
     * @param elem Element whose child is to be returned
     *
     * @return the first child element.
     */
    public static Element getFirstChildElement(Element elem) {
        return (Element) findChildByType(elem, Node.ELEMENT_NODE);
    }

    public static Node findChildByType(Element elem, int type) {
        if (elem == null)
            throw new NullPointerException("elem parameter must not be null!");

        for (Node n = elem.getFirstChild(); n != null; n = n.getNextSibling()) {
            if (n.getNodeType() == type) {
                return n;
            }
        }
        return null;
    }
}

Related

1. getFirstChildElement(Element e)
2. getFirstChildElement(Element e)
3. getFirstChildElement(Element e)
4. getFirstChildElement(Element ele)
5. getFirstChildElement(Element elem)
6. getFirstChildElement(Element elem)
7. getFirstChildElement(Element element)
8. getFirstChildElement(Element element)
9. getFirstChildElement(Element element)