Java XML Element Find getAllLeaveValues(Element element)

Description

get All Leave Values

License

Apache License

Declaration

public static List<String> getAllLeaveValues(Element element) throws XPathExpressionException 

Method Source Code

//package com.java2s;
/*//w  w  w  . j  a  v  a  2  s. co  m
 *    Copyright (c) 2013, University of Toronto.
 *
 *    Licensed under the Apache License, Version 2.0 (the "License"); you may
 *    not use this file except in compliance with the License. You may obtain
 *    a copy of the License at
 *
 *         http://www.apache.org/licenses/LICENSE-2.0
 *
 *    Unless required by applicable law or agreed to in writing, software
 *    distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
 *    WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
 *    License for the specific language governing permissions and limitations
 *    under the License.
 */

import java.util.LinkedList;
import java.util.List;

import javax.xml.xpath.XPathExpressionException;

import org.w3c.dom.Element;

import org.w3c.dom.Node;
import org.w3c.dom.NodeList;

public class Main {
    public static List<String> getAllLeaveValues(Element element) throws XPathExpressionException {
        if (element == null) {
            return null;
        }

        List<String> ret = new LinkedList<String>();
        if (isLeaf(element)) {
            ret.add(element.getTextContent());
        } else {
            NodeList nl = element.getChildNodes();
            for (int i = 0; i < nl.getLength(); i++) {
                Node n = nl.item(i);
                if (n instanceof Element) {
                    Element childElement = (Element) n;
                    for (String childText : getAllLeaveValues(childElement)) {
                        ret.add(childText);
                    }
                }
            }
        }

        return ret;
    }

    public static boolean isLeaf(Node node) {

        NodeList nodeList = node.getChildNodes();

        if (nodeList.getLength() == 0) {
            return true;
        }

        for (int i = 0; i < nodeList.getLength(); i++) {
            if (nodeList.item(i) instanceof Element) {
                // if the node contains child element it is not 
                // a leaf node
                return false;
            }
        }
        return true;
    }
}

Related

1. findNodeValue(Element firstElement, String name)
2. getAllElements(Element config, String elementName)
3. getAllElements(Element element)
4. getAllElements(Node context)
5. getAllElementsByTagName(Element elem, String name)
6. getAllNodeNames(Element ele)
7. getAllXmiIds(Element rootElement, String elementName)