Java XML Document Create getDocument(String docPath)

Here you can find the source of getDocument(String docPath)

Description

Gets XML Document for a given document path

License

Apache License

Parameter

Parameter Description
docPath the path to the XML file

Return

the XML Document object

Declaration


public static Document getDocument(String docPath)

        throws SAXException, IOException

    

Method Source Code

//package com.java2s;
/*//w ww . j  ava2s  .com
 * Copyright 2015 www.seleniumtests.com
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 * http://www.apache.org/licenses/LICENSE-2.0
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

import java.io.IOException;

import javax.xml.parsers.DocumentBuilder;

import org.w3c.dom.Document;

import org.xml.sax.SAXException;

public class Main {
    private static DocumentBuilder _docBuilder = null;

    /**
     * Gets XML Document for a given document path
     *
     * @param docPath the path to the XML file
     * @return the XML Document object
     * @see org.w3c.dom.Document
     */

    public static Document getDocument(String docPath)

            throws SAXException, IOException

    {

        return _docBuilder.parse(docPath);

    }
}

Related

  1. getDocument(InputStream xml)
  2. getDocument(InputStream xmlInputStream)
  3. getDocument(Node node)
  4. getDocument(Node parent)
  5. getDocument(Resource resource)
  6. getDocument(String fileName)
  7. getDocument(String filePath)
  8. getDocument(String payload)
  9. getDocument(String xml)