Here you can find the source of getChildNodes(Node parent, String childName)
public static List<Element> getChildNodes(Node parent, String childName)
//package com.java2s; /**/*from w ww . j ava2 s. c o m*/ * Copyright 2004-2009 Tobias Gierke <tobias.gierke@code-sourcery.de> * * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */ import java.util.ArrayList; import java.util.List; import org.w3c.dom.Element; import org.w3c.dom.Node; import org.w3c.dom.NodeList; public class Main { public static List<Element> getChildNodes(Node parent, String childName) { final List<Element> result = new ArrayList<Element>(); final NodeList nodes = parent.getChildNodes(); final int len = nodes.getLength(); for (int i = 0; i < len; i++) { final Node n = nodes.item(i); if (!isElementNode(n)) { continue; } if (n.getNodeName().equals(childName)) { result.add((Element) n); } } return result; } /** * Check whether a given XML <code>Node</code> is * an element node. * * Sun should've implemented <code>Node.hasType(int)</code>.... * * @param n * @return */ public static final boolean isElementNode(Node n) { return n != null && n.getNodeType() == Node.ELEMENT_NODE; } }