Java Utililty Methods XML Child Node Get

List of utility methods to do XML Child Node Get

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Description

The list of methods to do XML Child Node Get are organized into topic(s).

Method

StringgetChildNodeValue(Element root, String childNodeName, String defaultValue)
get Child Node Value 
NodeList nl = root.getElementsByTagName(childNodeName);
if (nl.getLength() == 1) {
    return getTextValue(nl.item(0)).trim();
} else if (defaultValue == null) {
    throw new SAXException("Node <" + root.getNodeName() + "> has no child named <" + childNodeName + ">");
} else {
    return defaultValue;
StringgetChildNodeValue(Node node, String elementName)
get Child Node Value 
return ((Element) node).getElementsByTagName(elementName).item(0).getTextContent();
StringgetChildNodeValue(Node root, String childName, boolean emptyStringOnMissingChild)
Instead of using XPathAPI.selectSingleNode(root, "name")); use getChildNodeValue(root, "name"); This is much quicker! 
NodeList nl = root.getChildNodes();
for (int i = 0; i < nl.getLength(); i++) {
    if (nl.item(i).getNodeName().equals(childName)) {
        Node textNode = nl.item(i).getFirstChild();
        if (textNode == null)
            return "";
        else
            return textNode.getNodeValue();
...
StringgetChildNodeValue(String childNodeName, Node n)
searches for a child of n called childNodeName. 
Node child = getChildNodeWithName(childNodeName, n);
return child.getNodeValue();
StringgetChildNodeValueByName(Node parent, String nodeName)
Gets a node value by name 
Node node = findChildNodeByName(parent, nodeName);
if (node != null && node.getFirstChild() != null) {
    return node.getFirstChild().getNodeValue().trim();
return "";
NodegetChildNodeWithName(Node node, String name, String namespaceURI)
get Child Node With Name 
List all = getChildNodesWithName(node, name, namespaceURI);
if (all.size() > 1) {
    throw new IllegalArgumentException("Expected only one node " + name + " for " + node);
if (all.size() > 0) {
    return (Node) all.get(0);
return null;
...
NodegetChildNodeWithName(String name, Node n)
looks through the child nodes of n and returns the first child with name 
NodeList nl = n.getChildNodes();
for (int i = 0; i < nl.getLength(); i++) {
    Node c = nl.item(i);
    if (c.getNodeName().equals(name)) {
        return c;
return null;
...
NodegetChildNodeWithTag(Node node, String nodeTag)
get Child Node With Tag 
NodeList elements = node.getChildNodes();
if (elements != null) {
    Node childNode;
    for (int i = 0; i < elements.getLength(); i++) {
        childNode = elements.item(i);
        if (childNode.getNodeName().equals(nodeTag))
            return childNode;
return null;