Java XML Child Get by Name getChildByName(Element parent, String name)

Description

get Child By Name

License

Apache License

Declaration

public static Element getChildByName(Element parent, String name) 

Method Source Code

//package com.java2s;
/*/* w w w  . j  a v  a2s . co m*/
 * Copyright 2009 Kantega AS
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *    http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;

public class Main {
    public static Element getChildByName(Element parent, String name) {
        NodeList children = parent.getChildNodes();
        if (children == null)
            return null;

        for (int i = 0; i < children.getLength(); i++) {
            Node child = children.item(i);
            if (child.getNodeName().equalsIgnoreCase(name)) {
                return (Element) child;
            }
        }

        return null;
    }
}

Related

1. getChildByName(Element parent, String name)
2. getChildByName(final Element parent, final String name)
3. getChildByName(final Element parent, final String name)
4. getChildByName(Node node, String name)
5. getChildByName(Node node, String name)