Java Wildcard to Regex wildcardAsRegex(String patternWithWildcards)

Description

converts a string containing wildcards (* and ?) into a valid regex

License

Apache License

Declaration

public static String wildcardAsRegex(String patternWithWildcards) 

Method Source Code

//package com.java2s;
/*//from   ww  w . j a v a2 s . c o  m
 * Licensed to the Apache Software Foundation (ASF) under one
 * or more contributor license agreements.  See the NOTICE file
 * distributed with this work for additional information
 * regarding copyright ownership.  The ASF licenses this file
 * to you under the Apache License, Version 2.0 (the
 * "License"); you may not use this file except in compliance
 * with the License.  You may obtain a copy of the License at
 *
 *   http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing,
 * software distributed under the License is distributed on an
 * "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY
 * KIND, either express or implied.  See the License for the
 * specific language governing permissions and limitations
 * under the License.
 */

public class Main {
    /** converts a string containing wildcards (* and ?) into a valid regex **/
    public static String wildcardAsRegex(String patternWithWildcards) {
        if (patternWithWildcards == null) {
            throw new IllegalArgumentException("patternWithWildcards must not be null");
        }
        return "\\Q" + patternWithWildcards.replace("?", "\\E.\\Q").replace("*", "\\E.*\\Q") + "\\E";
    }
}

Related

1. wildcard2Regex(final String wildcard)
2. wildcard2regexp(String wildcard)
3. wildcardAsRegex(String wildcard)
4. wildcardToJavaRegex(String expr)
5. wildcardToJavaRegexp(String expr)
6. wildcardToRegex(CharSequence s)