Java URL to Host Name getHostSegments(URL url)

Description

Partitions of the hostname of the url by "."

License

Apache License

Declaration

public static String[] getHostSegments(URL url) 

Method Source Code

//package com.java2s;
//License from project: Apache License 

import java.net.MalformedURLException;
import java.net.URL;

import java.util.regex.Pattern;

public class Main {
    private static Pattern IP_PATTERN = Pattern.compile("(\\d{1,3}\\.){3}(\\d{1,3})");

    /** Partitions of the hostname of the url by "."  */
    public static String[] getHostSegments(URL url) {
        String host = url.getHost();
        // return whole hostname, if it is an ipv4
        // TODO : handle ipv6
        if (IP_PATTERN.matcher(host).matches())
            return new String[] { host };
        return host.split("\\.");
    }//from  w w  w . ja  va  2 s  .  co  m

    /** Partitions of the hostname of the url by "."
     * @throws MalformedURLException */
    public static String[] getHostSegments(String url) throws MalformedURLException {
        return getHostSegments(new URL(url));
    }

    /**
     * Returns the lowercased hostname for the url or null if the url is not well
     * formed.
     * 
     * @param url The url to check.
     * @return String The hostname for the url.
     */
    public static String getHost(String url) {
        try {
            return new URL(url).getHost().toLowerCase();
        } catch (MalformedURLException e) {
            return null;
        }
    }
}

Related

1. getHostName(String url)
2. getHostName(String url)
3. getHostName(String url)
4. getHostName(String url)
5. getHostname(String urlStr)