Here you can find the source of getContainerUrl(URL url, String resourceInThatDir)
public static URL getContainerUrl(URL url, String resourceInThatDir)
//package com.java2s; /*//from www .ja v a 2 s . c o m * Copyright 2015 The Apache Software Foundation. * * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */ import java.io.IOException; import java.net.JarURLConnection; import java.net.MalformedURLException; import java.net.URL; public class Main { public static URL getContainerUrl(URL url, String resourceInThatDir) { //Switching from manual parsing of jar: and file: URLs to java provided functionality. //The old code was breaking on any Windows path and instead of fixing it, using //the provided Java APIs seemed like the better option since they are already tested //on multiple platforms. boolean isJar = "jar".equals(url.getProtocol()); if (isJar) { try { //let java handle the parsing of jar URL, no network connection is established. //Strips the jar protocol: // jar:file:/<path to jar>!<resourceInThatDir> // becomes // file:/<path to jar> JarURLConnection connection = (JarURLConnection) url .openConnection(); url = connection.getJarFileURL(); } catch (IOException e) { throw new IllegalStateException(e); } } else { //Remove the trailing resouceInThatDir path from the URL, thus getting the parent folder. String path = url.toString(); int i = path.indexOf(resourceInThatDir); if (i == -1) throw new IllegalStateException("Resource path (" + resourceInThatDir + ") not in url substring (" + url + ")"); String parent = path.substring(0, i); try { url = new URL(parent); } catch (MalformedURLException e) { throw new IllegalStateException("Resource (" + resourceInThatDir + ") found at invalid URL parent (" + parent + ")", e); } } return url; } }