Java URI to extractForwardURIFrom(URI requestURI)

Description

If no forward URI is given then return null.

License

Apache License

Parameter

Parameter	Description
requestURI	a parameter

Declaration

public static URI extractForwardURIFrom(URI requestURI) 

Method Source Code

//package com.java2s;
//License from project: Apache License 

import java.net.URI;

public class Main {
    /**//from   ww  w .ja v a 2s  . c o m
     * If no forward URI is given then return null.
     * @param requestURI
     * @return
     */
    public static URI extractForwardURIFrom(URI requestURI) {
        // http://localhost:8888http://boldapp26.dev.bol.com:9998/testspecs
        int http = requestURI.toString().indexOf("http", 4);
        if (http == -1)
            return null;
        return URI.create(requestURI.toString().substring(http));
    }
}

Related

1. convertToAbsPath(URI baseURI, String path)
2. convertToEncodedURIString(String input)
3. extractBaseUriFromRDF(String rdfString)
4. extractContentDigest(URI contentDigest)
5. extractFromURIParams(String paramsRule, String uri)
6. extractHostAddress(String uri)
7. extractHostname(String uri)
8. extractLocalName(String uri)