Java URI Create getURIFromEncodedString(String unencoded)

Here you can find the source of getURIFromEncodedString(String unencoded)

Description

get URI From Encoded String

License

Apache License

Declaration

public static URI getURIFromEncodedString(String unencoded)
            throws URISyntaxException, UnsupportedEncodingException 

Method Source Code


//package com.java2s;
/*/*from  ww  w  .j  a  v  a  2  s .c o m*/
 * Copyright 2016 Hurence
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 * http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 *
 */

import java.io.UnsupportedEncodingException;
import java.net.URI;
import java.net.URISyntaxException;

import java.net.URLEncoder;

public class Main {
    public static URI getURIFromEncodedString(String unencoded)
            throws URISyntaxException, UnsupportedEncodingException {

        URI uri;

        String[] split = unencoded.split("\\?");
        String part1 = split[0].replaceAll("\\[", URLEncoder.encode("[", "UTF8"))
                .replaceAll("\\]", URLEncoder.encode("]", "UTF8"))
                .replaceAll("\\|", URLEncoder.encode("|", "UTF8"));

        if (split.length < 2) {
            uri = new URI(part1);
        } else {

            uri = new URI(part1 + "?" + URLEncoder.encode(split[1], "UTF8"));
        }

        return uri;
    }
}

Related

  1. getURI(String spec)
  2. getUri(String uriName)
  3. getURIAddress(URI uri)
  4. getUriByEndpoint(String endpoint)
  5. getURIFilename(final String s)
  6. getURIFromPath(String fileOrURI)
  7. getURIFromPath(String path)
  8. getURIName(String forwardSlashPath)
  9. getURIName(URI uri)