Java String Sub String substringAfter(String s, String substr, boolean fromend)

Here you can find the source of substringAfter(String s, String substr, boolean fromend)

Description

Return the string after a given substring

License

Open Source License

Declaration

public static String substringAfter(String s, String substr, boolean fromend) 

Method Source Code

//package com.java2s;
/********************************************************************
Copyright (c) 2000-2008 Steven E. Hugg.//from  w  w  w .j av a 2  s. c om
    
This file is part of FLCore.
    
FLCore is free software: you can redistribute it and/or modify
it under the terms of the GNU Lesser General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
    
FLCore is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
GNU Lesser General Public License for more details.
    
You should have received a copy of the GNU Lesser General Public License
along with FLCore.  If not, see <http://www.gnu.org/licenses/>.
*********************************************************************/

public class Main {
    /**
      * Return the string after a given substring
      */
    public static String substringAfter(String s, String substr, boolean fromend) {
        int p = fromend ? s.lastIndexOf(substr) : s.indexOf(substr);
        return (p >= 0) ? s.substring(p + 1) : s;
    }
}

Related

  1. substring(StringBuffer buf, int start, int lim)
  2. substring2ByteString(String str, int endIndex)
  3. subString4lastIndex(String string, String regex)
  4. substringAfter(final String str, final String separator)
  5. substringAfter(String s, String cs)
  6. substringAfter(String sourceStr, String expr)
  7. substringAfter(String str, int beginChar, boolean last)
  8. substringAfter(String str, String delimiter)
  9. substringAfter(String str, String separator)