Here you can find the source of split(String str, String delim)
str/code> delimited by given delimiter delim
into string list.
License
Apache License
Parameter
Parameter Description str string to split delim delimiter set which delimit the token in the string, if it's null then use default value : space characters(" \t\r\n\f")
Return
string list contains tokens splitted by given delimiter
Declaration
public static List<String> split(String str, String delim)
Method Source Code
//package com.java2s;
//License from project: Apache License
import java.util.*;
public class Main {
/**//from ww w.j a v a2 s .co m
* Split the given string <code>str/code> delimited by given delimiter
* <code>delim</code> into string list.
* <p>Examples:
* <blockquote><pre>
* StringUtil.split("2005-05-01", "-") return list L[2005,05,01]
* StringUtil.split("2005 05 01", " ") return list L[2005,05,01]
* </pre></blockquote>
* @param str string to split
* @param delim delimiter set which delimit the token in the string, if it's
* null then use default value : space characters(" \t\r\n\f")
* @return string list contains tokens splitted by given delimiter
*/
public static List<String> split(String str, String delim) {
List<String> splitList = null;
StringTokenizer st = null;
if (str == null) {
return splitList;
}
if (isValid(delim)) {
st = new StringTokenizer(str, delim);
} else {
st = new StringTokenizer(str);
}
if ((st != null) && st.hasMoreTokens()) {
splitList = new ArrayList<String>();
while (st.hasMoreTokens()) {
splitList.add(st.nextToken());
}
}
return splitList;
}
/**
* Verify whether the given string <code>str</code> is valid. If the given
* string is not null and contains any alphabet or digit, then the string
* is think as valid, otherwise invalid.
* @param str string to verify
* @return false if the given string is null or contains only empty character,
* otherwise return true.
*/
public static boolean isValid(String str) {
boolean valid = true;
if ((str == null) || (str.trim().length() <= 0)) {
valid = false;
}
return valid;
}
}
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