Java String Shorten shortenStringsByRemovingVowelsToFit(String s1, String s2, int maximumStringLength)

Description

Returns a String which is a concatenation of two string which have had enough vowels removed from them so that the sum of the sized of the two strings is less than or equal to the specified size.

License

Open Source License

Declaration

public static String shortenStringsByRemovingVowelsToFit(String s1,
        String s2, int maximumStringLength) 

Method Source Code

//package com.java2s;
/*******************************************************************************
 * Copyright (c) 1998, 2015 Oracle and/or its affiliates. All rights reserved.
 * This program and the accompanying materials are made available under the
 * terms of the Eclipse Public License v1.0 and Eclipse Distribution License v. 1.0
 * which accompanies this distribution.//from   w w  w . j  av a  2  s. c o  m
 * The Eclipse Public License is available at http://www.eclipse.org/legal/epl-v10.html
 * and the Eclipse Distribution License is available at
 * http://www.eclipse.org/org/documents/edl-v10.php.
 *
 * Contributors:
 *     Oracle - initial API and implementation from Oracle TopLink
 *     dminsky - added countOccurrencesOf(Object, List) API
 *     08/23/2010-2.2 Michael O'Brien
 *        - 323043: application.xml module ordering may cause weaving not to occur causing an NPE.
 *                       warn if expected "_persistence_*_vh" method not found
 *                       instead of throwing NPE during deploy validation.
 ******************************************************************************/

public class Main {
    /**
     * Returns a String which is a concatenation of two string which have had enough
     * vowels removed from them so that the sum of the sized of the two strings is less than
     * or equal to the specified size.
     */
    public static String shortenStringsByRemovingVowelsToFit(String s1,
            String s2, int maximumStringLength) {
        int size = s1.length() + s2.length();
        if (size <= maximumStringLength) {
            return s1 + s2;
        }

        // Remove the necessary number of characters
        int s1Size = s1.length();
        int s2Size = s2.length();
        StringBuilder buf1 = new StringBuilder();
        StringBuilder buf2 = new StringBuilder();
        int numberOfCharsToBeRemoved = size - maximumStringLength;
        int s1Index = 0;
        int s2Index = 0;
        int modulo2 = 0;

        // While we still want to remove characters, and not both string are done.
        while ((numberOfCharsToBeRemoved > 0)
                && !((s1Index >= s1Size) && (s2Index >= s2Size))) {
            if ((modulo2 % 2) == 0) {
                // Remove from s1
                if (s1Index < s1Size) {
                    if (isVowel(s1.charAt(s1Index))) {
                        numberOfCharsToBeRemoved--;
                    } else {
                        buf1.append(s1.charAt(s1Index));
                    }
                    s1Index++;
                }
            } else {
                // Remove from s2
                if (s2Index < s2Size) {
                    if (isVowel(s2.charAt(s2Index))) {
                        numberOfCharsToBeRemoved--;
                    } else {
                        buf2.append(s2.charAt(s2Index));
                    }
                    s2Index++;
                }
            }
            modulo2++;
        }

        // Append the rest of the character that were not parsed through.
        // Is it quicker to build a substring and append that?
        while (s1Index < s1Size) {
            buf1.append(s1.charAt(s1Index));
            s1Index++;
        }
        while (s2Index < s2Size) {
            buf2.append(s2.charAt(s2Index));
            s2Index++;
        }

        //
        return buf1.toString() + buf2.toString();
    }

    /**
     * Returns true if the character given is a vowel. I.e. one of a,e,i,o,u,A,E,I,O,U.
     */
    public static boolean isVowel(char c) {
        return (c == 'A') || (c == 'a') || (c == 'e') || (c == 'E')
                || (c == 'i') || (c == 'I') || (c == 'o') || (c == 'O')
                || (c == 'u') || (c == 'U');
    }
}

Related

1. shortenString(String str, int i)
2. shortenString(String string, int minimumLength, int lengthToShortenBy)
3. shortenString(String string, int targetLength, int maxDeviation)
4. shortenStringForDisplay(String str, int desiredLen)
5. shortenStringIfNecessary(String string, int maxLength, String suffixToAppend)
6. shortenTagString(String longTag)
7. shortenText(final String text, final int maxLength, final boolean addDots)
8. shortenText(int maxWidth, String textValue)
9. shortenText(String originalText, int maxlength)