Java Utililty Methods String Pluralize

List of utility methods to do String Pluralize

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Description

The list of methods to do String Pluralize are organized into topic(s).

Method

Stringpluralize(int count, String singular, String plural)
Select singular or plural string based upon count. 
return (count == 1) ? singular : plural;
Stringpluralize(int count, String singular, String plural)
Returns a singlular or pluralized word. 
return (count == 1 ? singular : plural);
Stringpluralize(int count, String word)
pluralize 
return count == 1 ? word : word + 's';
StringPluralize(int quantity, String units)
Pluralize 
if (quantity == 1) {
    return quantity + " " + units;
} else {
    return quantity + " " + units + "s ";
Stringpluralize(int value, CharSequence singularForm, CharSequence pluralForm)
pluralize 
return Integer.toString(value) + " " + (value == 1 ? singularForm : pluralForm);
Stringpluralize(long count, String singularFormat, String pluralFormat)
pluralize 
return Math.abs(count) == 1 ? String.format(singularFormat, count) : String.format(pluralFormat, count);
Stringpluralize(long strictlyPositiveCount, String singular, String plural)
pluralize 
if (strictlyPositiveCount == 1) {
    return "1 " + singular + " ago";
return strictlyPositiveCount + " " + plural + " ago";
Stringpluralize(long val, String singular, String plural)
Determines whether the singular or plural version of a word should be used. 
return (val == 1) ? singular : plural;
Stringpluralize(String base, int quantity)
pluralize 
if (quantity == 1)
    return base;
else if (base.trim().toLowerCase().endsWith("s"))
    return base + "es";
else
    return base + "s";
Stringpluralize(String input)
Pluralize a property name, which is smart about things like nouns ending in 's' or 'y'. 
String result;
if (input.endsWith("ife")) {
    return input.substring(0, input.length() - 3) + "ives";
} else if (input.endsWith("s") || input.endsWith("sh") || input.endsWith("ch") || input.endsWith("x")
        || input.endsWith("z")) {
    result = input.concat("es");
} else if (input.endsWith("f") && !input.substring(input.length() - 2, 1).matches("[efo]")) {
    return input.substring(0, input.length() - 1) + "ves";
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