Java String Ends With endsWithIgnSpace(String s, String ending)

Here you can find the source of endsWithIgnSpace(String s, String ending)

Description

See if the given string ends with the given ending, IGNORING ALL SPACES IN THE INPUT STRING.

License

Open Source License

Parameter

Parameter Description
s The string to be checked
ending The ending we're looking for

Return

True iff s ends with "ending" regardless of spaces

Declaration

private static boolean endsWithIgnSpace(String s, String ending) 

Method Source Code

//package com.java2s;
/*//  w  w  w.j  av a  2 s  .com
 * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS HEADER.
 *
 * Copyright 1997-2010 Oracle and/or its affiliates. All rights reserved.
 *
 * Oracle and Java are registered trademarks of Oracle and/or its affiliates.
 * Other names may be trademarks of their respective owners.
 *
 * The contents of this file are subject to the terms of either the GNU
 * General Public License Version 2 only ("GPL") or the Common
 * Development and Distribution License("CDDL") (collectively, the
 * "License"). You may not use this file except in compliance with the
 * License. You can obtain a copy of the License at
 * http://www.netbeans.org/cddl-gplv2.html
 * or nbbuild/licenses/CDDL-GPL-2-CP. See the License for the
 * specific language governing permissions and limitations under the
 * License.  When distributing the software, include this License Header
 * Notice in each file and include the License file at
 * nbbuild/licenses/CDDL-GPL-2-CP.  Oracle designates this
 * particular file as subject to the "Classpath" exception as provided
 * by Oracle in the GPL Version 2 section of the License file that
 * accompanied this code. If applicable, add the following below the
 * License Header, with the fields enclosed by brackets [] replaced by
 * your own identifying information:
 * "Portions Copyrighted [year] [name of copyright owner]"
 *
 * Contributor(s):
 *
 * Portions Copyrighted 2008 Sun Microsystems, Inc.
 */

public class Main {
    /** See if the given string ends with the given ending, IGNORING ALL
     * SPACES IN THE INPUT STRING. E.g.  " foo b ar " is considered ending
     * with "foobar".  "=" and "-" are considered equivalent
     * (since this method is used for callseqs - => and -> are used
     * inconsistently.
     * 
     * @param s The string to be checked
     * @param ending The ending we're looking for
     * @return True iff s ends with "ending" regardless of spaces
     */
    private static boolean endsWithIgnSpace(String s, String ending) {
        int si = s.length() - 1;
        for (int ei = ending.length() - 1; ei >= 0; ei--, si--) {
            while (si >= 0 && Character.isWhitespace(s.charAt(si))) {
                si--;
            }
            if (si < 0) {
                return false;
            }

            char a = Character.toLowerCase(s.charAt(si));
            char b = Character.toLowerCase(ending.charAt(ei));
            if (a != b) {
                // Consider = and - to be equivalent
                if ((a == '=') || (a == '-') && (b == '=' || (b == '-'))) {
                    continue;
                }
                return false;
            }
        }
        return true;
    }
}

Related

  1. endsWithIgnoreCase(String str, String suffix)
  2. endsWithIgnoreCase(String string, String suffix)
  3. endsWithIgnoreCase(String target1, String target2)
  4. endsWithIgnoreCase(String text, String suffix)
  5. endsWithIgnoreCase(String toCheck, String suffix)
  6. endsWithIllegalWindowsChar(String filename)
  7. endsWithIndex(String[] suffixes, String propertyName)
  8. endsWithLineSeparator(final CharSequence msg)
  9. endsWithName(String subject, String endName)