Java String Camel Case To camelCaseMatch(String word, String abbr)

Description

Perfrom a String startsWith match with support for CamelCase.

License

Apache License

Parameter

Parameter	Description
word	full word
abbr	abbriviated word

Return

true if the word startsWith abbr, or if any uppercase char in abbr matches the next uppercase char in word FIXME: not so effecient as it creates a StringBuilder, but works FIXME: add Comparator

Declaration

public static boolean camelCaseMatch(String word, String abbr)

Method Source Code

//package com.java2s;
/*/*from  w  ww .ja  v a  2  s .c  om*/
 * Copyright 2008 Ayman Al-Sairafi ayman.alsairafi@gmail.com
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License
 *       at http://www.apache.org/licenses/LICENSE-2.0
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

public class Main {
    /**
     * Perfrom a String startsWith match with support for CamelCase.
     * @param word full word
     * @param abbr abbriviated word
     * @return true if the word startsWith abbr, or if any uppercase char in abbr
     * matches the next uppercase char in word
     *
     * FIXME: not so effecient as it creates a StringBuilder, but works
     * FIXME: add {@code Comparator<String, String>}
     */
    public static boolean camelCaseMatch(String word, String abbr) {
        StringBuilder sb = new StringBuilder();
        sb.append(word.charAt(0));
        for (int i = 1; i < word.length(); i++) {
            char c = word.charAt(i);
            if (Character.isUpperCase(c)) {
                sb.append(c);
            }
        }
        String cc = sb.toString();
        if (cc.startsWith(abbr)) {
            return true;
        } else {
            return word.startsWith(abbr);
        }
    }
}