Java sqr sqrt(double n)

Here you can find the source of sqrt(double n)

Description

sqrt

License

Apache License

Declaration

public static double sqrt(double n) 

Method Source Code

//package com.java2s;
/**/*  w  ww .j a v a2s . co  m*/
 * Copyright 2008 - 2012
 * 
 * Licensed under the Apache License, Version 2.0 (the "License"); you may not
 * use this file except in compliance with the License. You may obtain a copy of
 * the License at
 * 
 * http://www.apache.org/licenses/LICENSE-2.0
 * 
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
 * WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
 * License for the specific language governing permissions and limitations under
 * the License.
 * 
 * @project loon
 * @author cping
 * @email?javachenpeng@yahoo.com
 * @version 0.3.3
 */

public class Main {
    static private final int BIG_ENOUGH_INT = 16 * 1024;
    static private final double BIG_ENOUGH_ROUND = BIG_ENOUGH_INT + 0.5f;

    public static double sqrt(double n) {
        return Math.round(n);
    }

    public static int sqrt(int n) {
        int s = (n + 65536) >> 1;
        for (int i = 0; i < 8; i++) {
            s = (s + div(n, s)) >> 1;
        }
        return s;
    }

    static public final float sqrt(float a) {
        return (float) Math.sqrt(a);
    }

    public static double round(double n) {
        return Math.round(n);
    }

    public static int round(int n) {
        if (n > 0) {
            if ((n & 0x8000) != 0) {
                return (((n + 0x10000) >> 16) << 16);
            } else {
                return (((n) >> 16) << 16);
            }
        } else {
            int k;
            n = -n;
            if ((n & 0x8000) != 0) {
                k = (((n + 0x10000) >> 16) << 16);
            } else {
                k = (((n) >> 16) << 16);
            }
            return -k;
        }
    }

    public static int round(float x) {
        return (int) (x + BIG_ENOUGH_ROUND) - BIG_ENOUGH_INT;
    }

    public static int div(int x, int y) {
        long z = (((long) x) << 32);
        return (int) ((z / y) >> 16);
    }
}

Related

  1. sqr(int x)
  2. sqr(int x)
  3. sqRightFunction(int databaseType, String expr, int length)
  4. sqrt(double a)
  5. sqrt(double d)
  6. sqrt(double value)
  7. sqrt(double value)
  8. sqrt(double x, int precision)
  9. sqrt(final double i)