Java SQL Type extractConstant(String typeName)

Description

extract Constant

License

Apache License

Declaration

private static Integer extractConstant(String typeName) throws Exception 

Method Source Code

//package com.java2s;
/*/*from  w w w  .j a v a 2 s.com*/
 * Copyright 2014-2015 Victor Osolovskiy, Sergey Navrotskiy
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *     http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

import java.sql.Types;

public class Main {
    private static Integer extractConstant(String typeName) throws Exception {
        int lastDotPos = typeName.lastIndexOf(".");
        if (lastDotPos < 1) {
            throw new IllegalArgumentException("Type constant is not member of " + Types.class.getName()
                    + " and its name is not fully specified: " + typeName);
        }

        String className = typeName.substring(0, lastDotPos);
        String fieldName = typeName.substring(lastDotPos + 1);

        Class cls = Class.forName(className);
        Integer val = (Integer) cls.getField(fieldName).get(null);

        if (val == null)
            throw new NullPointerException(typeName);
        return val;
    }
}

Related

1. decodeJavaType(Object pType)
2. deleteData(Connection conn)
3. deleteFromAllTables(Connection con)
4. deserializeSQLTypesToJava(String sqltypename, String value)
5. dumpTypes(Connection pConnection)
6. fillLogParams(String sql, Map logParams)
7. findMethod(Class returnType, Class parameterType)
8. getAntipodeForFunction(String base, int destType)
9. getArgTypes()