Java Resource Get getResourceAsBytes(String resource)

Here you can find the source of getResourceAsBytes(String resource)

Description

Gets the resource as bytes.

License

Open Source License

Parameter

Parameter Description
resource the resource

Exception

Parameter Description
Exception the exception

Return

the resource as bytes

Declaration

static public byte[] getResourceAsBytes(String resource) throws Exception 

Method Source Code


//package com.java2s;
/*/*  w  w  w  .  j  a  v a2 s .  c  o m*/
 * Copyright (C) 2007-2008 Castafiore
 *
 * This program is free software; you can redistribute it and/or
 * modify it under the terms of the GNU Affero General Public License
 * as published by the Free Software Foundation; either version 3
 * of the License, or (at your option) any later version.
 *
 * This program is distributed in the hope that it will be useful,
 * but WITHOUT ANY WARRANTY; without even the implied warranty of
 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
 * GNU General Public License for more details.
 *
 * You should have received a copy of the GNU General Public License
 * along with this program; if not, see<http://www.gnu.org/licenses/>.
 */

import java.io.BufferedInputStream;

import java.io.ByteArrayOutputStream;

import java.io.InputStream;

import java.net.URL;

public class Main {
    /**
     * Gets the resource as bytes.
     *
     * @param resource the resource
     * @return the resource as bytes
     * @throws Exception the exception
     */
    static public byte[] getResourceAsBytes(String resource) throws Exception {
        ClassLoader cl = Thread.currentThread().getContextClassLoader();
        URL url = cl.getResource(resource);
        InputStream is = url.openStream();
        return getStreamContentAsBytes(is);
    }

    /**
     * Gets the stream content as bytes.
     *
     * @param is the is
     * @return the stream content as bytes
     * @throws Exception the exception
     */
    static public byte[] getStreamContentAsBytes(InputStream is) throws Exception {

        BufferedInputStream buffer = new BufferedInputStream(is);
        ByteArrayOutputStream output = new ByteArrayOutputStream();
        byte[] data = new byte[buffer.available()];
        if (buffer.available() == 0) {
            return data;
        }

        int available = -1;
        while ((available = buffer.read(data)) > -1) {
            output.write(data, 0, available);
        }
        return output.toByteArray();
    }
}

Related

  1. getResource(String name, Class neighbor)
  2. getResource(String name, Class caller)
  3. getResource(String res)
  4. getResource(String resource, Class context)
  5. getResourceAsBytes(String resource)
  6. getResourceAsFile(Class clazz, String resource)
  7. getResourceAsFile(Class klass, String resource)
  8. getResourceAsFile(Class sourceClass, String reference)
  9. getResourceAsFile(Class clazz, String fn)