Java Regex Version Validate parseVersion(String version, int defaultRevision)

Here you can find the source of parseVersion(String version, int defaultRevision)

Description

parse Version

License

Apache License

Declaration

private static int[] parseVersion(String version, int defaultRevision) 

Method Source Code


//package com.java2s;
/*/*from   ww  w  .  j  ava 2 s. co  m*/
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 * http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Main {
    private static final Pattern VERSION_REGEX = Pattern.compile("(\\d+)\\.(\\d+)(\\.(\\d+))?");

    private static int[] parseVersion(String version, int defaultRevision) {
        Matcher m = VERSION_REGEX.matcher(version);
        if (!m.matches()) {
            throw new IllegalArgumentException("invalid version string: \"" + version + "\"");
        }
        String revision = m.group(4);
        return new int[] { Integer.parseInt(m.group(1)), // major version number
                Integer.parseInt(m.group(2)), // minor version number
                revision == null ? defaultRevision : Integer.parseInt(revision), };
    }
}

Related

  1. parseVersion(final String versionString)
  2. parseVersion(String s, String groupId, String artifactId)
  3. parseVersion(String version, String currentVersion)
  4. parseVersionNamespace(String versionNamespace)