Java Regex URL Validate isUrl(String aUrl)

Description

Check if the URL complies with the expected pattern.

License

Apache License

Parameter

Parameter	Description
aUrl	The URL string to test.

Return

true if the URL meets the pattern; otherwise false.

Declaration

public static boolean isUrl(String aUrl) 

Method Source Code

//package com.java2s;
/*//from ww  w .ja v  a  2  s  .  co  m
 *  Copyright 2006 The National Library of New Zealand
 *
 *  Licensed under the Apache License, Version 2.0 (the "License");
 *  you may not use this file except in compliance with the License.
 *  You may obtain a copy of the License at
 *
 *      http://www.apache.org/licenses/LICENSE-2.0
 *
 *  Unless required by applicable law or agreed to in writing, software
 *  distributed under the License is distributed on an "AS IS" BASIS,
 *  WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 *  See the License for the specific language governing permissions and
 *  limitations under the License.
 */

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Main {
    /** Pattern for parsing URLs strings */
    private static Pattern PATTERN_HOST_PART = Pattern.compile("(http|https)://([^/]*)/(.*)");

    /**
     * Check if the URL complies with the expected pattern.
     * @param aUrl The URL string to test.
     * @return true if the URL meets the pattern; otherwise false.
     */
    public static boolean isUrl(String aUrl) {
        Matcher matcher = PATTERN_HOST_PART.matcher(aUrl);
        return matcher.matches();
    }
}

Related

1. isUri(String input)
2. isUrl(final String url)
3. isURL(String f)
4. isUrl(String s)
5. isUrl(String s)
6. IsUrl(String str)