Java Regex Time Validate parseTime(String t)

Description

parse Time

License

Open Source License

Declaration

public static long parseTime(String t) throws Exception 

Method Source Code

//package com.java2s;
//License from project: Open Source License 

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Main {
    public static long parseTime(String t) throws Exception {
        try {//ww w  .  j  a  v  a2s.  c o m
            if (!t.matches("[0-9]+d[a-z]*"))
                return Math.round(Double.parseDouble(t) * 60) * 1000;
            else {
                Pattern dayPattern = Pattern.compile("([0-9]+)d[a-z]*", Pattern.CASE_INSENSITIVE);
                Matcher m = dayPattern.matcher(t);

                if (m.matches()) {
                    return Integer.parseInt(m.group(1)) * 24 * 60 * 60 * 1000;
                }
            }
        } catch (NumberFormatException e) {
            Pattern hourPattern = Pattern.compile("([0-9]+)h[a-z]*", Pattern.CASE_INSENSITIVE);
            Pattern minPattern = Pattern.compile("([0-9]+)m[a-z]*", Pattern.CASE_INSENSITIVE);
            Pattern secPattern = Pattern.compile("([0-9]+)s[a-z]*", Pattern.CASE_INSENSITIVE);

            Matcher m = hourPattern.matcher(t);

            if (m.matches()) {
                return Integer.parseInt(m.group(1)) * 60 * 60 * 1000;
            }

            m = minPattern.matcher(t);

            if (m.matches()) {
                return Integer.parseInt(m.group(1)) * 60 * 1000;
            }

            m = secPattern.matcher(t);

            if (m.matches()) {
                return Integer.parseInt(m.group(1)) * 1000;
            }
        }
        throw new Exception("badtime");
    }
}

Related

1. parseTime(String s)
2. parseTime(String str)
3. parseTime(String value)
4. parseTimeDifference(String input)
5. parseTimeOffset(String s)
6. parseTimePeriod(String period)