Java Regex Number Validate parseNumbers(String str)

Description

parse Numbers

License

Apache License

Declaration

public static List<Double> parseNumbers(String str) 

Method Source Code

//package com.java2s;
/**/*from   w  w w .j ava 2s .c o m*/
 *
 * Licensed to the Apache Software Foundation (ASF) under one or more
 * contributor license agreements.  See the NOTICE file distributed with
 * this work for additional information regarding copyright ownership.
 * The ASF licenses this file to You under the Apache License, Version 2.0
 * (the "License"); you may not use this file except in compliance with
 * the License.  You may obtain a copy of the License at
 *
 *     http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 *
 */

import java.util.ArrayList;
import java.util.List;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Main {
    public static List<Double> parseNumbers(String str) {
        Pattern pattern = Pattern.compile("\\d+\\.*\\d*");
        Matcher m = pattern.matcher(str);

        List<Double> res = new ArrayList<Double>();
        while (m.find()) {
            String tmp = m.group().trim();
            res.add(Double.parseDouble(tmp));
        }
        return res.isEmpty() ? null : res;
    }

    public static boolean isEmpty(String str) {
        if (str == null || str.trim().equals(""))
            return true;
        return false;
    }
}

Related

1. isNumString(String txt)
2. parseNumber(String in)
3. parseNumber(String input)
4. parseNumber(String input)
5. parseNumber(String s)