Java Path File Name nio getLatestUpgradeScriptName(Path upgradeScriptsDir)

Here you can find the source of getLatestUpgradeScriptName(Path upgradeScriptsDir)

Description

get Latest Upgrade Script Name

License

Apache License

Declaration

private static String getLatestUpgradeScriptName(Path upgradeScriptsDir) throws IOException 

Method Source Code

//package com.java2s;
/*//from w  w w.  j a  v a  2s.  co m
 * Copyright 2014-2015 Red Hat Inc.
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *     http://www.apache.org/licenses/LICENSE-2.0
 *
 *     Unless required by applicable law or agreed to in writing, software
 *     distributed under the License is distributed on an "AS IS" BASIS,
 *     WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 *     See the License for the specific language governing permissions and
 *     limitations under the License.
 *
 */

import java.io.IOException;

import java.nio.file.DirectoryStream;
import java.nio.file.Files;
import java.nio.file.Path;

import java.util.ArrayList;
import java.util.Collections;
import java.util.List;

public class Main {
    private static String getLatestUpgradeScriptName(Path upgradeScriptsDir) throws IOException {
        List<String> fileNames = new ArrayList<>();
        DirectoryStream.Filter<Path> fileFilter = new DirectoryStream.Filter<Path>() {
            public boolean accept(Path file) throws IOException {
                return !Files.isDirectory(file);
            }
        };
        try (DirectoryStream<Path> directoryStream = Files.newDirectoryStream(upgradeScriptsDir, fileFilter)) {
            for (Path path : directoryStream) {
                // in schema_version table script name contains "upgrade/" prefix
                fileNames.add(path.subpath(path.getNameCount() - 2, path.getNameCount()).toString());
            }
        } finally {
        }
        Collections.sort(fileNames);
        return fileNames.get(fileNames.size() - 1);
    }
}

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