Java Path Extract nio extractClassName(Path path)

Description

Extracts the actual Class-Name from the given Path which should be a Path to a Class-File

If the given Path does not discribe a Class-File the result may be completly unusable

License

Open Source License

Declaration

public static String extractClassName(Path path) 

Method Source Code

//package com.java2s;
/* // w  w  w .j a  va  2  s  .  c o m
 * The MIT License
 *
 * Copyright 2016 Simon Berndt.
 *
 * Permission is hereby granted, free of charge, to any person obtaining a copy
 * of this software and associated documentation files (the "Software"), to deal
 * in the Software without restriction, including without limitation the rights
 * to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
 * copies of the Software, and to permit persons to whom the Software is
 * furnished to do so, subject to the following conditions:
 *
 * The above copyright notice and this permission notice shall be included in
 * all copies or substantial portions of the Software.
 *
 * THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
 * IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
 * FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
 * AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
 * LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
 * OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN
 * THE SOFTWARE.
 */

import java.nio.file.Path;
import java.util.Locale;

import javax.tools.JavaFileObject;

public class Main {
    private static final String CLASS_FILE_ENDING = JavaFileObject.Kind.CLASS.extension.toLowerCase(Locale.ROOT);

    /**
     * Extracts the actual Class-Name from the given Path which should be a Path to a Class-File
     * <p>
     * If the given Path does not discribe a Class-File the result may be completly unusable
     */
    public static String extractClassName(Path path) {
        String className = path.toString();
        return className.substring(1, className.length() - CLASS_FILE_ENDING.length()).replace('/', '.');
    }
}

Related

1. extract(Path archive, Path targetDirectory)
2. extractCurrentPath()
3. extractFile(ZipInputStream zipIn, Path filePath)
4. extractLanguageRelativePath(final Path absolutePath)
5. extractLuaStacktrace(Path path, StackTraceElement[] stackTrace)