Java Parse Number parseNumber(String number)

Here you can find the source of parseNumber(String number)

Description

Parses a string with the default locale and returns the corresponding number

License

Open Source License

Exception

Parameter Description
ParseException if number cannot be parsed

Declaration

public static double parseNumber(String number) throws ParseException 

Method Source Code

//package com.java2s;
/*/*from  w  w  w . j  ava 2 s  .co  m*/
 * Sonar, open source software quality management tool.
 * Copyright (C) 2008-2011 SonarSource
 * mailto:contact AT sonarsource DOT com
 *
 * Sonar is free software; you can redistribute it and/or
 * modify it under the terms of the GNU Lesser General Public
 * License as published by the Free Software Foundation; either
 * version 3 of the License, or (at your option) any later version.
 *
 * Sonar is distributed in the hope that it will be useful,
 * but WITHOUT ANY WARRANTY; without even the implied warranty of
 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
 * Lesser General Public License for more details.
 *
 * You should have received a copy of the GNU Lesser General Public
 * License along with Sonar; if not, write to the Free Software
 * Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA  02
 */

import java.text.NumberFormat;
import java.text.ParseException;
import java.util.Locale;

public class Main {
    /**
     * Parses a string with a locale and returns the corresponding number
     *
     * @throws ParseException if number cannot be parsed
     */
    public static double parseNumber(String number, Locale locale) throws ParseException {
        if ("".equals(number)) {
            return Double.NaN;
        }
        return NumberFormat.getNumberInstance(locale).parse(number).doubleValue();
    }

    /**
     * Parses a string with the default locale and returns the corresponding number
     *
     * @throws ParseException if number cannot be parsed
     */
    public static double parseNumber(String number) throws ParseException {
        return parseNumber(number, Locale.getDefault());
    }
}

Related

  1. parseNum(String numStr)
  2. parseNumber(CharacterIterator it)
  3. parseNumber(final String source, final String conversionPattern)
  4. parseNumber(String number)
  5. parseNumber(String s)
  6. parseNumber(String text, Class targetClass)
  7. parseNumber(String text, Class targetClass, NumberFormat numberFormat)
  8. parseNumber(String text, Class targetClass)