Here you can find the source of serializeAndDeserializeObject(Object myObject)
public static void serializeAndDeserializeObject(Object myObject)
//package com.java2s; /**/*from ww w. j a va 2 s . c o m*/ * Copyright 2009-2015 the original author or authors. * * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */ import java.io.ByteArrayInputStream; import java.io.ByteArrayOutputStream; import java.io.IOException; import java.io.ObjectInputStream; import java.io.ObjectOutputStream; public class Main { public static void serializeAndDeserializeObject(Object myObject) { try { deserialzeObject(serializeObject(myObject)); } catch (IOException e) { System.out.println("Exception: " + e.toString()); } } private static Object deserialzeObject(byte[] aSerializedObject) { try { // Deserialize from a byte array ObjectInputStream myObjectInputStream = new ObjectInputStream( new ByteArrayInputStream(aSerializedObject)); Object myResult = myObjectInputStream.readObject(); myObjectInputStream.close(); return myResult; } catch (Exception anException) { throw new RuntimeException("Problem deserializing", anException); } } private static byte[] serializeObject(Object myObject) throws IOException { try { ByteArrayOutputStream myByteArrayOutputStream = new ByteArrayOutputStream(); // Serialize to a byte array ObjectOutputStream myObjectOutputStream = new ObjectOutputStream(myByteArrayOutputStream); myObjectOutputStream.writeObject(myObject); myObjectOutputStream.close(); // Get the bytes of the serialized object byte[] myResult = myByteArrayOutputStream.toByteArray(); return myResult; } catch (Exception anException) { throw new RuntimeException("Problem serializing: " + anException.toString(), anException); } } }