Java Utililty Methods Long Number Create

List of utility methods to do Long Number Create

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Description

The list of methods to do Long Number Create are organized into topic(s).

Method

int[]convertLongtoMultiByte(long val)
convert Longto Multi Byte 
int size;
if ((val >> 56) > 0) {
    size = 8;
} else if ((val >> 48) > 0) {
    size = 7;
} else if ((val >> 40) > 0) {
    size = 6;
} else if ((val >> 32) > 0) {
...
intfromLong(byte[] buffer, int pos, long l)
from Long 
buffer[pos] = (byte) ((l >> 56) & 255);
buffer[pos + 1] = (byte) ((l >> 48) & 255);
buffer[pos + 2] = (byte) ((l >> 40) & 255);
buffer[pos + 3] = (byte) ((l >> 32) & 255);
buffer[pos + 4] = (byte) ((l >> 24) & 255);
buffer[pos + 5] = (byte) ((l >> 16) & 255);
buffer[pos + 6] = (byte) ((l >> 8) & 255);
buffer[pos + 7] = (byte) (l & 255);
...
voidfromLong(long value, byte[] arr, int offset)
from Long 
value ^= 1L << 63;
arr[offset] = (byte) (value >>> 56);
arr[offset + 1] = (byte) (value >>> 48);
arr[offset + 2] = (byte) (value >>> 40);
arr[offset + 3] = (byte) (value >>> 32);
arr[offset + 4] = (byte) (value >>> 24);
arr[offset + 5] = (byte) (value >>> 16);
arr[offset + 6] = (byte) (value >>> 8);
...
longfromLongLE(byte src[], int offset, int numBytes)
Little endian, i.e. 
if (numBytes <= 0 || numBytes > 8)
    throw new IllegalArgumentException("Invalid number of bytes");
long rv = 0;
for (int i = offset + numBytes - 1; i >= offset; i--) {
    rv <<= 8;
    rv |= src[i] & 0xFF;
if (rv < 0)
...
longtoLong(boolean b)
Return the long value of the boolean.
If boolean is TRUE this will return 1, else 0. 
if (b) {
    return 1L;
return 0L;
longtoLong(boolean... a)
Packs boolean array to integer, the booleans with greater indices go first 
if (a.length >= 64) {
    throw new IllegalArgumentException(
            "while packing boolean array in int, the array length should be less than 32");
int n = 0;
for (int i = (a.length - 1); i >= 0; --i) {
    n = (n << 1) | (a[i] ? 1 : 0);
return n;
longtoLong(byte b)
to Long 
return 0xff & b;
longtoLong(byte byte7, byte byte6, byte byte5, byte byte4, byte byte3, byte byte2, byte byte1, byte byte0)
Convert 8 bytes into a long. 
return toLong(toInt(byte7, byte6, byte5, byte4), toInt(byte3, byte2, byte1, byte0));
longtoLong(byte... b)
to Long 
long l = 0;
int len = b.length;
for (int i = 0; i < len && i < 8; i++) {
    l = (long) l << 8 | byte2UnsignInt(b[i]);
return l;
longtoLong(byte... b)
to Long 
int mask = 0xff;
int temp = 0;
long res = 0;
int byteslen = b.length;
if (byteslen > 8) {
    return Long.valueOf(0L);
for (int i = 0; i < byteslen; i++) {
...