Java List Sort getOverlapCount(List list1, List list2, boolean sorted)

Description

get Overlap Count

License

Apache License

Declaration

public static <T extends Comparable<T>> int getOverlapCount(List<T> list1, List<T> list2, boolean sorted) 

Method Source Code

//package com.java2s;
/**/*from   w  w w  .  j  a  v a2s. com*/
 * Copyright 2015, Emory University
 * 
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 * 
 *     http://www.apache.org/licenses/LICENSE-2.0
 * 
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

import java.util.Collections;

import java.util.List;

public class Main {
    public static <T extends Comparable<T>> int getOverlapCount(List<T> list1, List<T> list2, boolean sorted) {
        if (!sorted) {
            Collections.sort(list1);
            Collections.sort(list2);
        }

        if (list1.size() > list2.size()) {
            List<T> temp = list1;
            list1 = list2;
            list2 = temp;
        }

        T l1_ele, l2_ele;
        int i = 0, j = 0, comp, count = 0, size1 = list1.size(), size2 = list2.size();

        for (; i < size1; i++) {
            l1_ele = list1.get(i);

            for (; j < size2; j++) {
                l2_ele = list2.get(j);

                comp = l1_ele.compareTo(l2_ele);
                if (comp > 0)
                    continue;
                else if (comp == 0) {
                    j++;
                    count++;
                }
                break;
            }
        }

        return count;
    }
}

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