Java List Move Item getLongestLine(String text, List partsToRemove, String separator)

Description

get Longest Line

License

LGPL

Declaration

public static String getLongestLine(String text, List<String> partsToRemove, String separator) 

Method Source Code

//package com.java2s;
/*/*from w w  w. ja va 2s. co  m*/
Strandz LGPL - an API that matches the user to the data.
Copyright (C) 2007 Chris Murphy
    
Strandz LGPL is free software; you can redistribute it and/or
modify it under the terms of the GNU Lesser General Public
License as published by the Free Software Foundation; either
version 2.1 of the License, or (at your option) any later version.
    
This library is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
Lesser General Public License for more details.
    
You should have received a copy of the GNU Lesser General Public
License along with this library; if not, write to the Free Software
Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA  02110-1301  USA
    
    
The authors can be contacted via www.strandz.org
*/

import java.util.List;

public class Main {
    public static String getLongestLine(String text, List<String> partsToRemove, String separator) {
        String result = null;
        String toInvestigate = removeParts(text, partsToRemove);
        String longest = "";
        String words[] = toInvestigate.split(separator);
        for (int i = 0; i < words.length; i++) {
            String word = words[i];
            if (word.length() > longest.length()) {
                longest = word;
            }
        }
        if (!longest.equals("")) {
            result = longest;
        }
        return result;
    }

    public static String removeParts(String text, List<String> parts) {
        String result;
        if (text != null) {
            for (int i = 0; i < parts.size(); i++) {
                String part = parts.get(i);
                while (text.contains(part)) {
                    text = remove(text, part);
                }
            }
        }
        result = text;
        return result;
    }

    /**
     * If result == in then nothing happened so don't do it again
     *
     * @param in
     * @param toRemove
     * @return
     */
    public static String remove(String in, String toRemove) {
        String result = in;
        int index = in.indexOf(toRemove);
        if (index != -1) {
            String before = in.substring(0, index);
            String after = in.substring(index + toRemove.length(), in.length());
            result = before.concat(after);
        }
        return result;
    }
}

Related

1. addRemoveChangeToString(int from, int to, List list, List removed)
2. canMoveUp(List list, int[] indices)
3. getRemoveAll(List list1, Collection list2)
4. minus(List initialList, List elementsToRemove)
5. move(List aList, int anIndex1, int anIndex2)
6. move(List collection, int indexToMoveFrom, int indexToMoveAt)