Java List Merge merge(List list, int split)

Here you can find the source of merge(List list, int split)

Description

Merges two consecutive sorted lists in place.

License

Open Source License

Parameter

Parameter Description
list The <code>List</code> to sort.
split The number of elements in the first sub-list.

Declaration

public static <T extends Comparable<? super T>> void merge(List<T> list, int split) 

Method Source Code

//package com.java2s;
/**//from   w  w w .j  av a 2s  .com
 * Java Modular Image Synthesis Toolkit (JMIST)
 * Copyright (C) 2008-2013 Bradley W. Kimmel
 *
 * Permission is hereby granted, free of charge, to any person
 * obtaining a copy of this software and associated documentation
 * files (the "Software"), to deal in the Software without
 * restriction, including without limitation the rights to use,
 * copy, modify, merge, publish, distribute, sublicense, and/or sell
 * copies of the Software, and to permit persons to whom the
 * Software is furnished to do so, subject to the following
 * conditions:
 *
 * The above copyright notice and this permission notice shall be
 * included in all copies or substantial portions of the Software.
 *
 * THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND,
 * EXPRESS OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES
 * OF MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND
 * NONINFRINGEMENT. IN NO EVENT SHALL THE AUTHORS OR COPYRIGHT
 * HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER LIABILITY,
 * WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING
 * FROM, OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR
 * OTHER DEALINGS IN THE SOFTWARE.
 */

import java.util.Collections;
import java.util.List;

public class Main {
    /**
     * Merges two consecutive sorted lists in place.
     * The two sub-lists
     * <code>list.get(0), ..., list.get(split-1)</code> and
     * <code>list.get(split), ..., list.get(list.size() - 1)</code>
     * must be sorted.  The results are undefined otherwise.
     * @param list The <code>List</code> to sort.
     * @param split The number of elements in the first sub-list.
     */
    public static <T extends Comparable<? super T>> void merge(List<T> list, int split) {
        int n = list.size();
        if (0 < split && split < n) {
            merge(list, 0, split, n - 1, (int) Math.sqrt(split), 0);
        }
    }

    /**
     * Merges two consecutive sorted lists in place.
     *
     * <p>This implementation is based on:</p>
     *
     * <p>J. Chen, "<a href="http://dx.doi.org/10.1016/j.ipl.2005.11.018">A
     * simple algorithm for in-place merging</a>", Information Processing
     * Letters 98:34-40, 2006.</p>.
     *
     * This algorithm is a direct transcription of Fig. 3 on page 37 of this
     * paper, plus the two modifications indicated in the last paragraph of
     * Sec. 2 (page 38) to increase the efficiency using recursion and to
     * allow the algorithm to "work correctly when y<sub>0</sub> - x<sub>0</sub>
     * &lt; 2k".
     *
     * @param A The <code>List</code> to be merged.
     * @param x0 The index of the start of the first sub-list.
     * @param y0 The index of the start of the second sub-list.
     * @param yn The index of the end of the second sub-list.
     * @param k The block size.
     * @param depth The recursion depth.
     */
    private static <T extends Comparable<? super T>> void merge(List<T> A, int x0, int y0, int yn, int k,
            int depth) {
        int f = (y0 - x0) % k;
        int x = (f == 0) ? (y0 - 2 * k) : (y0 - k - f);
        if (x < x0) {
            x = x0;
        }
        T t = A.get(x);
        A.set(x, A.get(x0));
        int z = x0, y = y0, b1 = x + 1, b2 = y0 - k;
        while ((y - z) > (2 * k)) {
            if (y > yn || A.get(x).compareTo(A.get(y)) <= 0) {
                A.set(z, A.get(x));
                A.set(x, A.get(b1));
                x++;
                if (((x - x0) % k) == f) {
                    if (z < (x - k)) {
                        b2 = x - k;
                    }
                    x = findNextXBlock(A, x0, z, y, k, f, b1, b2);
                }
            } else {
                A.set(z, A.get(y));
                A.set(y, A.get(b1));
                y++;
                if (((y - y0) % k) == 0) {
                    b2 = y - k;
                }
            }
            z++;
            A.set(b1, A.get(z));
            if (z == x) {
                x = b1;
            }
            if (z == b2) {
                b2 = -1;
            }
            b1++;
            if (((b1 - x0) % k) == f) {
                if (b2 == -1) {
                    b1 -= k;
                } else {
                    b1 = b2;
                }
            }
        }
        A.set(z, t);
        if (depth > 0) {
            mergeBandY(A, z, y, yn);
        } else {
            Collections.sort(A.subList(z, y));
            merge(A, z, y, yn, (int) Math.sqrt(k), 1);
        }
    }

    /**
     * Auxilliary method required for merging two consecutive sorted lists in
     * place.
     *
     * <p>This implementation is based on:</p>
     *
     * <p>J. Chen, "<a href="http://dx.doi.org/10.1016/j.ipl.2005.11.018">A
     * simple algorithm for in-place merging</a>", Information Processing
     * Letters 98:34-40, 2006.</p>.
     *
     * This method is a direct transcription of Fig. 4.
     */
    private static <T extends Comparable<? super T>> int findNextXBlock(List<T> A, int x0, int z, int y, int k,
            int f, int b1, int b2) {
        T min1 = null, min2 = null;
        int m = (int) Math.floor(((z - x0 - f) / (double) k)) * k + f + x0;
        if (m <= z) {
            m += k;
        }
        int i = m;
        int j, x = i;
        while ((i + k) <= y) {
            if ((i != b1) && (i != b2)) {
                if ((i < b1) && (b1 < i + k)) {
                    j = m - 1;
                } else {
                    j = i + k - 1;
                }
                if (min1 == null || (A.get(i).compareTo(min1) <= 0 && A.get(j).compareTo(min2) <= 0)) {
                    x = i;
                    min1 = A.get(i);
                    min2 = A.get(j);
                }
            }
            i += k;
        }
        return x;
    }

    /**
     * Auxilliary method required for merging two consecutive sorted lists in
     * place.
     *
     * <p>This implementation is based on:</p>
     *
     * <p>J. Chen, "<a href="http://dx.doi.org/10.1016/j.ipl.2005.11.018">A
     * simple algorithm for in-place merging</a>", Information Processing
     * Letters 98:34-40, 2006.</p>.
     *
     * This method is a direct transcription of Fig. 5.
     */
    private static <T extends Comparable<? super T>> void mergeBandY(List<T> A, int z, int y, int yn) {
        while (z < y && y <= yn) {
            int j = z + indexOfMin(A.subList(z, y));
            if (A.get(j).compareTo(A.get(y)) <= 0) {
                Collections.swap(A, z, j);
            } else {
                Collections.swap(A, z, y);
                y++;
            }
            z++;
        }
        if (z < y) {
            Collections.sort(A.subList(z, yn + 1));
        }
    }

    /**
     * Finds the first index of a minimal element in a list.
     * @param list The <code>List</code> to search.
     * @return The first index of a minimal element in the list.
     */
    public static <T extends Comparable<? super T>> int indexOfMin(List<T> list) {
        T min = list.get(0);
        int index = 0;
        for (int i = 0, n = list.size(); i < n; i++) {
            T value = list.get(i);
            if (value.compareTo(min) < 0) {
                min = value;
                index = i;
            }
        }
        return index;
    }
}

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