Java List Max findMax(List nums)

Description

find Max

License

Apache License

Declaration

public static double findMax(List<Double> nums) 

Method Source Code

//package com.java2s;
/**//w  ww  .  j  a v a 2  s .c om
 *
 * Licensed to the Apache Software Foundation (ASF) under one or more
 * contributor license agreements.  See the NOTICE file distributed with
 * this work for additional information regarding copyright ownership.
 * The ASF licenses this file to You under the Apache License, Version 2.0
 * (the "License"); you may not use this file except in compliance with
 * the License.  You may obtain a copy of the License at
 *
 *     http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 *
 */

import java.util.List;

public class Main {
    public static double findMax(List<Double> nums) {
        double m = Double.MIN_VALUE;
        for (Double x : nums) {
            if (m < x)
                m = x;
        }
        return m;
    }
}

Related

1. findMax(List values)
2. findMaxDeformationCount(final List counts)
3. findMaximalMatch(List> mapList, LinkedHashMap fieldsByPriority)
4. getMax(List numList)