List of utility methods to do List Distinct Value
boolean | addDistinctEntry(List add distinct entry to list return (sourceList != null && !sourceList.contains(entry)) ? sourceList.add(entry) : false;
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void | addDistinctItems(List add Distinct Items for (String fromItem : fromItems) { if (!toItems.contains(fromItem)) { toItems.add(fromItem); |
int | addDistinctList(List add Distinct List if (sourceList == null || isEmpty(entryList)) { return 0; int sourceCount = sourceList.size(); for (V entry : entryList) if (!sourceList.contains(entry)) { sourceList.add(entry); return sourceList.size() - sourceCount; |
Long | addWithExpDecay(List add With Exp Decay Collections.sort(distinctVals, Collections.reverseOrder()); long denom = distinctVals.get(0); for (int i = 1; i < distinctVals.size(); i++) { denom = (long) (denom * Math.pow(distinctVals.get(i), 1.0 / (1 << i))); return denom; |
void | constructDistinctClause(StringBuffer selectClause, List construct Distinct Clause String distinctClause; if (attributes == null || attributes.isEmpty()) { distinctClause = DISTINCT.concat(ROOT_OBJ_ALIAS); } else { distinctClause = DISTINCT; for (Iterator<String> iterator = attributes.iterator(); iterator.hasNext();) { String attr = (String) iterator.next(); distinctClause = distinctClause.concat(ROOT_OBJ_ALIAS + DOT + attr); ... |
List | distinct(List distinct int m = 0; List<String> strList = new ArrayList<String>(); for (int i = 0; i < list.size(); i++) { for (int j = 0; j < list.size(); j++) { if (list.get(i).trim().equals(list.get(j).trim())) { if (i != j) { m = j; list.remove(m); ... |
List | distinct(List distinct return null;
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List | distinct(List distinct List<T> distinctVector = new ArrayList<T>(); vector.stream().distinct().forEach(s -> distinctVector.add(s)); return distinctVector; |
int | distinctList(List distinct List if (isEmpty(sourceList)) { return 0; int sourceCount = sourceList.size(); int sourceListSize = sourceList.size(); for (int i = 0; i < sourceListSize; i++) for (int j = (i + 1); j < sourceListSize; j++) { if (sourceList.get(i).equals(sourceList.get(j))) { ... |
String[] | getDistinctStrings(String[] list) this method takes out all of the duplicate strings. ArrayList distincts = new ArrayList(list.length); for (int i = 0; i < list.length; i++) { if (!distincts.contains(list[i])) { distincts.add(list[i]); return toArray(distincts); |