Here you can find the source of isIPAddress(String ipAddress)
public static boolean isIPAddress(String ipAddress)
//package com.java2s; /*//from w ww . j av a 2 s.c o m * xAuth for Bukkit * Copyright (C) 2012 Lycano <https://github.com/lycano/xAuth/> * * Copyright (C) 2011 CypherX <https://github.com/CypherX/xAuth/> * * This program is free software: you can redistribute it and/or modify * it under the terms of the GNU General Public License as published by * the Free Software Foundation, either version 3 of the License, or * (at your option) any later version. * * This program is distributed in the hope that it will be useful, * but WITHOUT ANY WARRANTY; without even the implied warranty of * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the * GNU General Public License for more details. * * You should have received a copy of the GNU General Public License * along with this program. If not, see <http://www.gnu.org/licenses/>. */ import java.util.regex.Matcher; import java.util.regex.Pattern; public class Main { public static boolean isIPAddress(String ipAddress) { if (ipAddress == null) return false; Pattern pattern = Pattern.compile("\\b" + "((?!\\d\\d\\d)\\d+|1\\d\\d|2[0-4]\\d|25[0-5])\\." + "((?!\\d\\d\\d)\\d+|1\\d\\d|2[0-4]\\d|25[0-5])\\." + "((?!\\d\\d\\d)\\d+|1\\d\\d|2[0-4]\\d|25[0-5])\\." + "((?!\\d\\d\\d)\\d+|1\\d\\d|2[0-4]\\d|25[0-5])" + "\\b"); Matcher matcher = pattern.matcher(ipAddress); return matcher.matches(); } }