Java InputStream Deserialize to Object deserializeInt(InputStream in)

Description

deserialize Int

License

Open Source License

Declaration

public static Integer deserializeInt(InputStream in) 

Method Source Code

//package com.java2s;
/* /*from  w  w w . j  a va 2  s  .com*/
 * This file is part of the HyperGraphDB source distribution. This is copyrighted 
 * software. For permitted uses, licensing options and redistribution, please see  
 * the LicensingInformation file at the root level of the distribution.  
 * 
 * Copyright (c) 2005-2010 Kobrix Software, Inc.  All rights reserved. 
 */

import java.io.IOException;
import java.io.InputStream;

public class Main {
    public static Integer deserializeInt(InputStream in) {
        try {
            int ch1 = in.read();
            int ch2 = in.read();
            int ch3 = in.read();
            int ch4 = in.read();
            int i = ((ch1 & 0xFF) << 24) | ((ch2 & 0xFF) << 16) | ((ch3 & 0xFF) << 8) | (ch4 & 0xFF);

            return new Integer(i);
        } catch (IOException ex) {
            ex.printStackTrace();
        }
        return null;
    }
}

Related

1. deserialize(InputStream sourceInputStream, Class objectType)
2. deserialize(ObjectInputStream stream)
3. deserialize(String input, Class tClass)
4. deserializeFromStram(InputStream inputStram)
5. deserializeFromStream(ObjectInputStream in)
6. deserializeSpecial(InputStream is, Class clazz)
7. deserializeUUID(InputStream in)