Here you can find the source of toIntArray(InetAddress addr)
Parameter | Description |
---|---|
addr | the source address to convert. |
public static int[] toIntArray(InetAddress addr)
//package com.java2s; /*//from ww w . j ava 2 s .co m * JPPF. * Copyright (C) 2005-2010 JPPF Team. * http://www.jppf.org * * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */ import java.net.*; import java.util.regex.Pattern; public class Main { /** * Convert an IP address int array. * @param addr the source address to convert. * @return an array of int values, or null if the source could not be parsed. */ public static int[] toIntArray(InetAddress addr) { try { byte[] bytes = addr.getAddress(); String ip = addr.getHostAddress(); int[] result = null; if (addr instanceof Inet6Address) { result = new int[8]; String[] comp = ip.split(":"); for (int i = 0; i < comp.length; i++) result[i] = Integer .decode("0x" + comp[i].toLowerCase()); } else { result = new int[8]; String[] comp = ip.split("\\."); for (int i = 0; i < comp.length; i++) result[i] = Integer.valueOf(comp[i]); } return result; } catch (Exception e) { return null; } } /** * Convert a string with <code>separator</code>-separated values into an int array. * @param source the source string to convert. * @param separatorPattern the values separator, expressed as a regular expression, must comply with the specifications for {@link java.util.regex.Pattern}. * @return an array of int value, or null if the source cvould not be parsed. */ public static int[] toIntArray(String source, Pattern separatorPattern) { try { String[] vals = separatorPattern.split(source); int[] result = new int[vals.length]; for (int i = 0; i < vals.length; i++) result[i] = Integer.valueOf(vals[i]); return result; } catch (Exception e) { return null; } } }