Java Utililty Methods Hex Convert To

List of utility methods to do Hex Convert To

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Description

The list of methods to do Hex Convert To are organized into topic(s).

Method

byte[]fromHexString(byte abyte0[], int i)
from Hex String 
int j = 0;
if (abyte0[0] == 48 && (abyte0[1] == 120 || abyte0[1] == 88)) {
    j += 2;
    i -= 2;
int k = i / 2;
byte abyte1[] = new byte[k];
for (int l = 0; l < k;) {
...
byte[]fromHexString(final String hexaString)
Creates a ByteBuffer whose content is represented as hexadecimal in the given String. 
if ((hexaString.length() % 2) != 0) {
    throw new IllegalArgumentException("Input string must contain an even number of characters");
int length = hexaString.length();
byte[] buf = new byte[length / 2];
for (int i = 0; i < length; i += 2) {
    buf[i / 2] = (byte) ((Character.digit(hexaString.charAt(i), 16) << 4)
            + Character.digit(hexaString.charAt(i + 1), 16));
...
byte[]fromHexString(final String hexString)
Converts the provided String of hexadecimal numbers (with optional leading "0x") into a byte[] of the same value. 
if (hexString == null) {
    return null;
String str = hexString.trim().toLowerCase();
if (str.startsWith("0x")) {
    str = str.substring(2);
int numChars = str.length();
...
byte[]fromHexString(final String s)
Creates byte array representation of HEX string.
int length = s.length() / 2;
byte[] bytes = new byte[length];
for (int i = 0; i < length; i++) {
    bytes[i] = (byte) (Character.digit(s.charAt(i * 2), 16) << 4
            | Character.digit(s.charAt(i * 2 + 1), 16));
return bytes;
byte[]fromHexString(final String str)
from Hex String 
if ((str.length() % 2) != 0)
    throw new IllegalArgumentException(ERROR_INPUT_STRING_NUM_CHARS);
byte[] result = new byte[str.length() / 2];
for (int i = 0; i < str.length() / 2; i++) {
    result[i] = (Integer.decode(STR_HEX_PREFIX + str.substring(i * 2, (i + 1) * 2))).byteValue();
return result;
byte[]fromHexString(String encoded)
Returns a byte array of a given string by converting each character of the string to a number base 16 
if ((encoded.length() % 2) != 0)
    throw new IllegalArgumentException("Input string must contain an even number of characters."); 
final byte result[] = new byte[encoded.length() / 2];
final char enc[] = encoded.toCharArray();
for (int i = 0; i < enc.length; i += 2) {
    StringBuilder curr = new StringBuilder(2);
    curr.append(enc[i]).append(enc[i + 1]);
    result[i / 2] = (byte) Integer.parseInt(curr.toString(), 16);
...
byte[]fromHexString(String encoded)
from Hex String 
encoded = removeSpaces(encoded);
if (encoded.length() == 0) {
    return new byte[0];
if ((encoded.length() % 2) != 0) {
    throw new IllegalArgumentException(
            "Input string must contain an even number of characters: " + encoded);
final byte result[] = new byte[encoded.length() / 2];
final char enc[] = encoded.toCharArray();
for (int i = 0; i < enc.length; i += 2) {
    StringBuilder curr = new StringBuilder(2);
    curr.append(enc[i]).append(enc[i + 1]);
    result[i / 2] = (byte) Integer.parseInt(curr.toString(), 16);
return result;
byte[]fromHexString(String hex)
from Hex String 
return fromHex(hex.getBytes());
byte[]fromHexString(String hex)
Converts the given hex string to a byte array. 
int len = hex.length();
if (len % 2 != 0)
    throw new IllegalArgumentException("Not a hex string");
byte[] bytes = new byte[len / 2];
for (int i = 0, j = 0; i < len; i += 2, j++) {
    int high = hexDigitToInt(hex.charAt(i));
    int low = hexDigitToInt(hex.charAt(i + 1));
    bytes[j] = (byte) ((high << 4) + low);
...
byte[]fromHexString(String hexString)
From hex string. 
if (hexString != null) {
    int strlen = hexString.length();
    int blen = strlen / 2 + strlen % 2;
    byte[] barray = new byte[blen];
    int i = 0;
    int j = 0;
    if (strlen % 2 > 0) {
        hexString = "0" + hexString;
...