Here you can find the source of readTextFile(String fullPathFilename)
Parameter | Description |
---|---|
fullPathFilename | a parameter |
Parameter | Description |
---|---|
IOException | an exception |
public static String readTextFile(String fullPathFilename) throws IOException
//package com.java2s; /*/* www . j a v a 2s . c o m*/ * Copyright (C) 2011 NATSRL @ UMD (University Minnesota Duluth, US) and * Software and System Laboratory @ KNU (Kangwon National University, Korea) * * This program is free software: you can redistribute it and/or modify * it under the terms of the GNU General Public License as published by * the Free Software Foundation, either version 3 of the License, or * (at your option) any later version. * * This program is distributed in the hope that it will be useful, * but WITHOUT ANY WARRANTY; without even the implied warranty of * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the * GNU General Public License for more details. * * You should have received a copy of the GNU General Public License * along with this program. If not, see <http://www.gnu.org/licenses/>. */ import java.io.BufferedReader; import java.io.FileReader; import java.io.IOException; public class Main { /** * Method readTextFile. Uses a FileReader to populate a buffer of chars. * The chars are appended to a StringBuffer and returned as a String to the caller. * The FileReader uses the default file encoding scheme for the OS. * @param fullPathFilename * @return String * @throws IOException */ public static String readTextFile(String fullPathFilename) throws IOException { StringBuilder sb = new StringBuilder(1024); BufferedReader reader = new BufferedReader(new FileReader(fullPathFilename)); char[] chars = new char[1024]; int numRead = 0; while ((numRead = reader.read(chars)) > -1) { sb.append(String.valueOf(chars, 0, numRead)); } reader.close(); return sb.toString(); } }