Here you can find the source of getFileNameAndExt(String s)
public static String getFileNameAndExt(String s)
//package com.java2s; /*//from w w w. j a v a 2 s . c om * Armadillo Workflow Platform v1.0 * A simple pipeline system for phylogenetic analysis * * Copyright (C) 2009-2011 Etienne Lord, Mickael Leclercq * * This program is free software: you can redistribute it and/or modify * it under the terms of the GNU General Public License as published by * the Free Software Foundation, either version 3 of the License, or * (at your option) any later version. * * This program is distributed in the hope that it will be useful, * but WITHOUT ANY WARRANTY; without even the implied warranty of * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the * GNU General Public License for more details. * * You should have received a copy of the GNU General Public License * along with this program. If not, see <http://www.gnu.org/licenses/>. */ import java.io.File; import java.io.IOException; import java.io.PrintWriter; public class Main { public PrintWriter log; public boolean log_open = false; /** * Get the file name with it's extension from a string * Added by JG 2017 * @in string path ex: ./path/to/file/file.f * @return file name ex: file.f */ public static String getFileNameAndExt(String s) { if (s != "") { String tmp = getCanonicalPath(s); int pos1 = tmp.lastIndexOf(File.separator); int pos2 = tmp.length(); if (pos1 > 0 && pos2 > pos1 + 1) return tmp.substring(pos1 + 1, pos2); } return s; } /** * Get the canonical path from string * Added by JG 2016 * @param s path ex: ./path/to/file/file.f * @return CanonicalPath ex: /home/user/path/to/file/file.f */ public static String getCanonicalPath(String s) { File f = new File(s); try { s = f.getCanonicalPath(); } catch (IOException ex) { System.out.println("Get Canonical Path Failed!"); System.out.println(ex); ex.printStackTrace(); } return s; } public void println(String str) { if (log_open) log.println(str); } }